Posted by **Ginger** on Saturday, November 27, 2010 at 3:31pm.

Find the vertex and axis of symmetry of the graph of a function.

f(x)=x^2+6x+16

- Math -
**drwls**, Saturday, November 27, 2010 at 4:27pm
f(x) = x^2+6x+16

= x^2 +6x +9 +3

= (x+3)^2 +3

The vertex (lowest point) is x= -3, y = 3. That is because (x+3)^2 can never ne negative.

It is symmetrical about the x=-3 vertical line.

- College Math -
**Henry**, Sunday, November 28, 2010 at 2:01pm
f(x) = x^2 + 6x + 16.

h = Xv = -b / 2a = -6 / 2 = -3,

Substitute -3 for x in the given Eq:

k = Yv = (-3)^2 + 6*-3 16,

k = 9 - 18 + 16 = 25 - 18 = 7,

V(h , k) = V(-3 , 7).

Axis: h = Xv = -3. = A vertical line

where x isconstant at -3 for all values of y.

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