A laboratory centrifuge on earth makes n rpm (rev/min) and produces an acceleration of 7.00 g at its outer end.

What is the acceleration (in g's, i.e., acceleration divided by g) at a point halfway out to the end?

half as much. It is proportional to r.

To find the acceleration at a point halfway out to the end of the laboratory centrifuge, we can use the concept of centrifugal acceleration.

Centrifugal acceleration is given by the formula:

a = ω² * r,

where:
- a is the acceleration,
- ω is the angular velocity (in radians per second), and
- r is the radius.

To convert the given rotational speed from rpm to radians per second, we can use the conversion factor:

1 revolution = 2π radians.

Therefore, the angular velocity ω is calculated as follows:

ω = (n * 2π) / 60,

where:
- n is the rotational speed in rpm.

Let's calculate the angular velocity:

ω = (n * 2π) / 60.

Next, we need to determine the radius at the midpoint. Since the acceleration is measured at the outer end and we want to find the acceleration halfway out, we can divide the radius at the outer end by 2.

Finally, we can substitute the calculated values into the formula for centrifugal acceleration to find the acceleration at the midpoint.

Let's put it all together and calculate the acceleration at the midpoint.