posted by flame on .
The electrochemical cell described by the cell notation has an Eo of -0.37 V. Calculate the maximum electrical work (kJ) the cell has done if 331.73 g of Cu(s) (Molar Mass - 63.55 g/mol) reacts. Round your answer to 3 significant figures.
Cu(s) l Cu+(aq) ll Sn4+(aq), Sn2+(aq) l Pt(s)
St. Red. Pot. (V)
F = 96485 C
convert 331g to mole= 5.21
G=-nFE=2(5.21)(96485)(-.37)=372kJ, why do i have to divide it in half to get 186kJ