Posted by Back against the wall on Friday, November 26, 2010 at 9:38pm.
let u = lnx
then du = dx/x
∫1/[x*(lnx+1] dx
= ∫(1/(u+1) du
= ln(u+1) + C
= ln[lnx+1)] + C
When x = 1, the indefinite integral is 0
When x =e^7, the indefinite integral is ln8. The C terms can be ignored since they cancel out.
ln8 is the answer
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