Posted by **jay** on Friday, November 26, 2010 at 7:32pm.

A quarterback throws the football to a stationary receiver who is 22.7 m down the field.The football is thrown at an initial angle of 39◦ to the ground.

The acceleration of gravity is 9.81 m/s2 .

a) At what initial speed must the quarter-

back throw the ball for it to reach the receiver?

- physics -
**Damon**, Friday, November 26, 2010 at 7:44pm
S is the speed

horizontal speed = u = S cos 39

22.7 = u t

so t = 22.7/u

in the air to that time t

Vo = S sin 39

h = 0 + Vo t - 4.9 t^2

h = 0 at the end as well as at t = 0

so

Vo t = 4.9 t^2

t = 0 ( not a help) or t = Vo/4.9

so

Vo/4.9 = 22.7/u

22.7 *4.9 = 111 = Vo u

111 = S sin 39 * S cos 39

S^2 = 111/(sin 39 cos 39)

- physics -
**jay**, Friday, November 26, 2010 at 8:11pm
What is the ballâ€™s highest point during its flight? please

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