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physics

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A quarterback throws the football to a stationary receiver who is 22.7 m down the field.The football is thrown at an initial angle of 39◦ to the ground.
The acceleration of gravity is 9.81 m/s2 .
a) At what initial speed must the quarter-
back throw the ball for it to reach the receiver?

  • physics -

    S is the speed
    horizontal speed = u = S cos 39

    22.7 = u t
    so t = 22.7/u

    in the air to that time t
    Vo = S sin 39
    h = 0 + Vo t - 4.9 t^2
    h = 0 at the end as well as at t = 0
    so
    Vo t = 4.9 t^2
    t = 0 ( not a help) or t = Vo/4.9

    so
    Vo/4.9 = 22.7/u
    22.7 *4.9 = 111 = Vo u
    111 = S sin 39 * S cos 39

    S^2 = 111/(sin 39 cos 39)

  • physics -

    What is the ball’s highest point during its flight? please

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