TRIG
posted by rossi .
what is the exact value of sin^2 pi/62 sin pi/6 cos pi/6 +cos^2 (pi/6)?
a) 2 sqrt 3
b) 2 sqrt 3/ 2
c) 2+ sqrt 3/2
d) 2+ sqrt 3
I am not sure how to work this out and would appreciate you how to show me the process. Thank you in advanced!!!!!!!

sin pi/6 = sin 30 deg = 1/2
cos pi/6 = .5 sqrt 3
cos x = cos x
so
1/4  .5 sqrt 3 + 3/4
1  .5 sqrt 3
(2  sqrt 3 ) / 2