Posted by **Nicole** on Friday, November 26, 2010 at 12:27pm.

solve the following for x, where 0<x<2pi.... 2tanx+ sq rt 12=0

- write the general solution aswell

- Math -
**Reiny**, Friday, November 26, 2010 at 12:53pm
2 tanx = -√12

tanx = -√12/2

x = 60° or 240°

since the period of tanx is 180°

the general solution would be 60° + 180k

now I will switch to radians

x = π/3 or 4π/3

general solution : x = π/3 + kπ , where k is an integer

(I used my calculator to find the first angle, even though I should have recognized √12/2 as √3

I usually set my calculator to degrees, that way I recognize the standard angles if there are any.

Unless you recognize the decimal versions of radian angles, this works best for me)

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