Posted by **AMY** on Friday, November 26, 2010 at 11:23am.

Write an equation of the the line containing the given point and perpendicular to the given line. (7,-5); 9x+7y = 3.

What I have so far. y-9=(1/9(x-3). Not sure after this.

- Algebra/equations -
**Reiny**, Friday, November 26, 2010 at 11:34am
First of all the new slope should have been 7/9.

Now you have to use the given point this way ...

y + 5 = (7/9)(x-7)

multiply each side by 9 (I don't like fractions in my equations)

9y + 45 = 7x - 49

-7x + 9y = -93

7x - 9y = 93

A quick way to do the above..

If Ax + By = C is the equation , then

the line Bx - Ay = K is perpendicular to it,

so

if 9x + 7y = 3 is given , then

7x - 9y = k is the perpendicular line

sub in the given point ...

7(7) - 9(-9) = c = 93

7x - 9y = 93 is your new line

- Algebra/equations -
**AMY**, Friday, November 26, 2010 at 12:59pm
thank u

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