posted by javane on .
A helicopter is rising at 5.5 m/s when a bag of its cargo is dropped. (Assume that the positive direction is upward.)
(a) After 1.5 s, what is the bag's velocity?
(b) How far has the bag fallen?
(a) v = v0 + at, v0 = 5.5 m/s, a = -g = -9.80 m/s.
(b) y = y0 + v0t + (1/2)at2
y-y0 = v0t + (1/2)at2
at2 is acceleration x time squared.