Posted by javane on .
An 879-kg (1943 lb) dragster, starting from rest, attains a speed of 25.6 m/s (57.3 mph) in 0.59 s.
(a) Find the average acceleration of the dragster during this time interval.
(b) What is the magnitude of the average net force on the dragster during this time?
I am not going to do all these for you. They are all basically the same.
a = (V2-V1)/t = (25.6-0)/.59 = 43.4 m/s^2
F = m a = 879 * 43.4 = 38,140 Newtons