Tuesday

September 2, 2014

September 2, 2014

Posted by **Sarah** on Thursday, November 25, 2010 at 6:12am.

standard deviation of 6. If 4 fish are randomly selected, what is the probability that the mean

weight will be between 8.6 and 14.6 lb?

A) 0.0968 B) 0.4032 C) 0.3270 D) 0.6730

- Statistics -
**PsyDAG**, Thursday, November 25, 2010 at 10:28amZ = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√(n-1)

If only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions related to the Z scores.

- Statistics -
**Sarah**, Sunday, November 28, 2010 at 3:55ami still dont get how to do it?

**Answer this Question**

**Related Questions**

Statistics - The weights of the fish in a certain lake are normally distributed ...

statistics - the lenght of a species of fish is normally distributed with a mean...

statistics - The weights of certain machine components are normally distributed ...

Statistics - Assume there are two lakes containing trout and the weights of the ...

statistics - The actual weights of bag of pet food are normally distributed.The ...

Statistics - The weights of adult males are normally distributed with a mean of ...

statistics - The weights of a group of adult males are normally distributed with...

Statistics - Construct a 95% confidence interval for population mean: My friends...

Math (Statistics) - (Find Normal Proportions) The lengths of Atlantic croaker ...

Statistics - The actual weights of bag of pet food are normally distributed.The ...