Posted by **Sarah** on Thursday, November 25, 2010 at 6:12am.

The weights of the fish in a certain lake are normally distributed with a mean of 11 lb and a

standard deviation of 6. If 4 fish are randomly selected, what is the probability that the mean

weight will be between 8.6 and 14.6 lb?

A) 0.0968 B) 0.4032 C) 0.3270 D) 0.6730

- Statistics -
**PsyDAG**, Thursday, November 25, 2010 at 10:28am
Z = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√(n-1)

If only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions related to the Z scores.

- Statistics -
**Sarah**, Sunday, November 28, 2010 at 3:55am
i still don't get how to do it?

## Answer This Question

## Related Questions

- stats - the weights of the fish in a certain lake are normally distributed with ...
- stats - so the question is: the weights of fish in a certain lake are normally ...
- Statistics - The weights of the fish in a certain lake are normally distributed ...
- statistics - An automatic machine that fills bags of unpopped popcorn is ...
- statistics - An automatic machine that fills bags of unpopped popcorn is ...
- math - Bass: The bass in Clear Lake have weights that are normally distributed ...
- Statistics - An engineer is going to redesign an ejection seat for an airplane. ...
- statistics - The weights of steers in a herd are distributed normally. The ...
- statistics - Individual M&M plain candies have weights that are normally ...
- math - Weights of women are normally distributed with mean 143 pounds and ...

More Related Questions