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April 2, 2015

April 2, 2015

Posted by **Indigo** on Wednesday, November 24, 2010 at 10:02pm.

I tried this question, and apparently the answer isn't 45 mph. It's something of a trick question. Any help/hints would be much appreciated!

- Algebra II -
**Reiny**, Wednesday, November 24, 2010 at 10:56pmAverage speed = total distance / total time

time for first trip = d/40

time for return trip = d/50

total time = d/40 + d/50 = 9d/200

total distance = 2d

avg speed = 2d/(9d/200) = 400/9 = 44.444.. mph

- Algebra II -
**Indigo**, Saturday, November 27, 2010 at 10:54amThank you!

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