Posted by **ted** on Wednesday, November 24, 2010 at 6:29pm.

The city bus company usually transports 12000 riders per day at a ticket price of $1. The company wants to raise the tickets price and knows that for every 10 cents increase, the number of riders decreases by 400.

A. What price for a ticket will maximize revenue?

pls help

- math -
**Damon**, Wednesday, November 24, 2010 at 7:22pm
n riders, q price increase over 100 pennies in pennies

n = 12000 (1 - 400 *10q)

r = n ( 100 + q)

so

r = 12000 (1-4000q)(100+q)

r = 12000 (100 -399,999 q - 4,000q^2)

dr/dq = 12000 (-399,999 - 8,000 q)

max when 0

q = about -50 cents

looks like they should lower the price to 50 cents to maximize revenue

If you do not do calculus find the vertex of the parabola

40 q^2 + 4000q -1 = 0

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