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April 20, 2014

April 20, 2014

Posted by **tom** on Wednesday, November 24, 2010 at 2:08pm.

(a) Assuming a circular orbit, what is the orbital period of this satellite?

(b) What is the satellite's speed in its orbit?

(c) What is the minimum energy necessary to place the satellite in orbit, assuming no air friction?

J

- Physics -
**drwls**, Wednesday, November 24, 2010 at 2:20pmFor (a) and (b), the satellite mass will not matter. The orbit distance from the center of the earth is R = 6378 + 210 = 6588 km. Speed is

V = 2 pi R/P

where P is the period.

Get the period from

G M/R^2 = V^2/R

G M = V^2*R = 4 pi^2 R^3/P^2

Solve for P

M is the earth's mass

Energy required = (1/2) m V^2 + GMm[1/Re - (1/(Re + 211,000m)]

m is the satellite mass

There is a small additional term (+ or - that takes into account the rotational speed of the earth at the launch point. That gives the rocket launcher a bit of a boost, especially at the equator.

- Physics -
**derp**, Tuesday, November 6, 2012 at 10:00pmI need a better explanation than that, and an answer to show you are right. thanks

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