Posted by tom on Wednesday, November 24, 2010 at 2:08pm.
For (a) and (b), the satellite mass will not matter. The orbit distance from the center of the earth is R = 6378 + 210 = 6588 km. Speed is
V = 2 pi R/P
where P is the period.
Get the period from
G M/R^2 = V^2/R
G M = V^2*R = 4 pi^2 R^3/P^2
Solve for P
M is the earth's mass
Energy required = (1/2) m V^2 + GMm[1/Re - (1/(Re + 211,000m)]
m is the satellite mass
There is a small additional term (+ or - that takes into account the rotational speed of the earth at the launch point. That gives the rocket launcher a bit of a boost, especially at the equator.
I need a better explanation than that, and an answer to show you are right. thanks
Related Questions
Physics - A satellite of mass 220 kg is launched from a site on Earth's ...
physics - Estimate the energy required from fuel to launch a 1465 kg satellite ...
Physics help PLZ!! - Estimate the energy required from fuel to launch a 1465 kg ...
physics - Two Earth satellites, A and B, each of mass m, are to be launched into...
physics - Two Earth satellites, A and B, each of mass m, are to be launched into...
Physics - A 360-kg satellite is in orbit around the Earth 10000 km above the ...
Physics please help - How far from the center of the Earth (in km) is the center...
Physics help! - How far from the center of the Earth (in km) is the center of ...
physics - On July 15, 2004, NASA launched the Aura spacecraft to study the earth...
Physics - A communications satellite with a mass of 450 kg is in a circular ...
For Further Reading
