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December 21, 2014

December 21, 2014

Posted by **Star** on Wednesday, November 24, 2010 at 1:18pm.

5(0.10)^x = 4(0.12)^x

- Math -
**Henry**, Thursday, November 25, 2010 at 3:50pm5(0.10)^x = 4(0.12)^x.

Take log of both sides:

log5 + xlog(0.10) = log4 + xlog(0.12)0.6990 - x = 0.6021 - 0.9208x,

-x + 0.9208x = 0.6021 - 0.6990,

-0.0792x = -0.0969,

X = -0.0969 / -0.0792 = 1.22.

- Math -
**Henry**, Thursday, November 25, 2010 at 4:06pmCORRECTION:

Take log of both sides:

log5 + Xlog(0.10) = log4 + Xlog(0.12),

0.6990 - X = 0.6021 - 0.9208X,

-x + 0.9208X = 0.6021- 0.6990,

-0.0792X = -0.0969,

X = -0.0969 / -0.0792 = 1.22.

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