Posted by **Becky** on Wednesday, November 24, 2010 at 1:03pm.

Give vertex, axis, x-intercepts and y-intercepts to parabola

y= -3x^2-6x+4

- Math -
**Henry**, Thursday, November 25, 2010 at 2:30pm
Y = -3X^2 - 6X + 4.

Vertex Form: y = a(x - h)^2 + k.

h = Xv = -b/2a = 6/-6 = -1.

Substitute -1 for x in the given Eq:

k = -3(-1)^2 - 6(-1) + 4=3 + 6 + 4 = 7.

V(h , k) = V(-1 , 7).

Vertex Form: y = -3(x + 1)^2 + 7.

Axis = h =Xv = -1.

The axis is a vertical line and equals

-1 for all values of y.

Let x = 0 and solve for y:

y = 3*0^2 - 6*0 + 4 = 4 = Y-Int.

The solutions,x-Intercepts, and roots

are all the same.

x = (6 +- sqrt(6^2 + 48)) / -6,

x = (6 +- sqrt(84)) / -6,

x = (6 +- 9.17) / -6,

x = (6 + 9.17) /-6 = - 2.5275.

x = (6 - 9.17) / -6 = 0.5275.

Solution set: x = -2.5275, x = 0.5275.

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