Posted by **JAZZY** on Wednesday, November 24, 2010 at 9:55am.

A rectangle has length & width in the ratio of 3:2.If the length is increased by 8 & width is increased by 50%.The ratio of new perimeter to original perimeter is 8:5.Find the area of new rectangle

- maths -
**Reiny**, Wednesday, November 24, 2010 at 11:44am
let the length be 3x and

let the width be 2x

new length = 3x + 8

new width = 1.5(2x) = 3x

original perimeter = 2(3x) + 2(2x) = 10x

new perimeter = 2(3x+8)+ 2(3x)

= 12x + 16

(12x+16)/(10x) = 8/5

80x = 60x + 80

20x = 80

x = 40

so new length = 3(40)+8 = 128

new width = 3(40) = 120

new area = 128x120 = 15360

use the suitable units, you gave none.

- error - maths -
**Reiny**, Wednesday, November 24, 2010 at 12:34pm
"20x = 80

x = 40 "

How silly of me ! , that should have been

x = 4

so new rectangle is 20 by 12 for an area of 240

- maths -
**brelan**, Monday, April 7, 2014 at 2:58pm
5yd 6yd u

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