Posted by **JAZZY** on Wednesday, November 24, 2010 at 9:15am.

A rectangle has legth & width in the ratio of 3:2.If the length is increased by 8 & width is increased by 50%.The ratio of new perimeter to origial perimeter is 8:5.Find the area of new rectangle.

- Maths -
**drwls**, Wednesday, November 24, 2010 at 9:39am
Your period after 50% should be a comma.

Let the old length and width be a and b, and the new values A and B

a = (3/2)b

A = B + 8

B = 1.5 b

A+B = (8/5)(a+b)

You need to solve four equations in four unknowns. Once you get A and B, the area is A*B

a + b = (5/2)b

A + B = 2B +8

A + B = (8/5)(a+b)

2B +8 = (8/5)(a+b) = 4 b

B = 2b -4 = (3/2)b

0.5b = 4

b = 8

a = (3/2)b = 12

A = B +8 = 20

B = A -8 = 12

A*B = 240 is the new area

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