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A rectangle has legth & width in the ratio of 3:2.If the length is increased by 8 & width is increased by 50%.The ratio of new perimeter to origial perimeter is 8:5.Find the area of new rectangle.

  • Maths - ,

    Your period after 50% should be a comma.
    Let the old length and width be a and b, and the new values A and B
    a = (3/2)b
    A = B + 8
    B = 1.5 b
    A+B = (8/5)(a+b)

    You need to solve four equations in four unknowns. Once you get A and B, the area is A*B

    a + b = (5/2)b
    A + B = 2B +8
    A + B = (8/5)(a+b)

    2B +8 = (8/5)(a+b) = 4 b
    B = 2b -4 = (3/2)b
    0.5b = 4
    b = 8
    a = (3/2)b = 12
    A = B +8 = 20
    B = A -8 = 12
    A*B = 240 is the new area

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