Posted by Tara on Wednesday, November 24, 2010 at 8:25am.
Hi Tara,
To find out if a reaction is spontaneous, we calculate E(cell). If E(cell)>0, reaction is spontaneous. If E(cell)<0, reaction is not spontaneous. If E(cell)=0, reaction will proceed until equilibrium is established.
So in this case, E(cell) = E(reduction)-E(oxidation) = 0.15V - (-2.37V) = 2.52V >0 hence reaction is spontaneous.
In this case, Mg is oxidized to Mg2+ as it loses 2 electrons while Cu2+ is reduced to Cu+ as it gains 1 electron.
Hope I helped! (:
-J
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