Posted by **sandhu** on Wednesday, November 24, 2010 at 4:29am.

The firetruck goes around a 180°, 162 m radius circular curve. It enters the curve with a speed of 12.6 m/s and leaves the curve with a speed of 38.8 m/s. Assuming the speed changes at a constant rate, what is the magnitude of the total acceleration of the firetruck just after it has entered the curve?

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**MathMate**, Wednesday, November 24, 2010 at 8:16am
From the length of the curve (L=πr), calculate the average tangential acceleration, At

= (38.8-12.6)/L

Find the radial acceleration due to curvature at entry to curve (v=12.6m/s)

Ar=v²/r

=12.6²/r

Since the two accelerations are perpendicular to each other, add Ar and At vectorially.

- physics -
**sandhu**, Wednesday, November 24, 2010 at 7:50pm
I don't understand how you get At = (38.8 - 12.6)/L.Please explain

Thanks.

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