Posted by **sandhu** on Wednesday, November 24, 2010 at 4:29am.

The firetruck goes around a 180°, 162 m radius circular curve. It enters the curve with a speed of 12.6 m/s and leaves the curve with a speed of 38.8 m/s. Assuming the speed changes at a constant rate, what is the magnitude of the total acceleration of the firetruck just after it has entered the curve?

- physics -
**MathMate**, Wednesday, November 24, 2010 at 8:16am
From the length of the curve (L=πr), calculate the average tangential acceleration, At

= (38.8-12.6)/L

Find the radial acceleration due to curvature at entry to curve (v=12.6m/s)

Ar=v²/r

=12.6²/r

Since the two accelerations are perpendicular to each other, add Ar and At vectorially.

- physics -
**sandhu**, Wednesday, November 24, 2010 at 7:50pm
I don't understand how you get At = (38.8 - 12.6)/L.Please explain

Thanks.

## Answer this Question

## Related Questions

- physics - 1.A firetruck is traveling at a velocity of +20 m/s in the x direction...
- physics - 1.A firetruck is traveling at a velocity of +20 m/s in the x direction...
- physics - Posted by sandhu on Wednesday, November 24, 2010 at 4:29am. The ...
- College math - Highway curves If a circular curve without any banking has a ...
- College math - Highwq curves. If a circular curve without any banking has a ...
- Physics - The fast French train known as the TGV (Train à Grande Vitesse) has a ...
- AP PHYSICS - The fast train known as teh TGV that runs south from Paris, France...
- Physics - A car drives around a curve with radius 150 m at a speed of 30 m/s. ...
- Physics - A car can be driven around a 120 m radius curve at constant speed ...
- physics - A block is hung by a string from the inside roof of a van. When the ...

More Related Questions