Posted by serena on Tuesday, November 23, 2010 at 10:20pm.
We confirm the concept of the geothermal effect in an alternative fashion to the discussion in the text. We know that the average rate at which heat is conducted through the surface of the ground in North America is 54.0 mJ/(s m2). Assuming a surface temperature of 2 oC, what is the temperature at a depth of 29.86 km? Hint: Ignore the heat generated by the presence of radioactive elements and use 2.5 J/(m s K) for the average thermal conductivity of the nearsurface rocks. Start with Fourier's law.
What process would I use to answer this?

physics  drwls, Wednesday, November 24, 2010 at 4:27am
Consider a 29.86 km thick layer as planar (since is a small fcraction of the earth's radius), with temperature T on one side and 2C on the other.
Then k*[T  (2)]/29.86*10^3m
is the heat conducted per area to the surface. You have been given a value for that. You also have been given a value for k. Use those values to solve for T, the temperature at 29.86 km depth