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Posted by sandhu on Tuesday, November 23, 2010 at 7:13pm.

A 33300 lb (earth weight) rocket in outer space has two constant forces acting upon it, F1 = (-166i + 392j) lb and F2 = (50i + -54j) lb. Its initial velocity is (39i + 64j) ft/s. How far is it from where it started after 33 seconds?

The net force is F1 + F2 = -116 i + 338 j In the x direction, the final location is changed by 39*33 + (1/2)(-116/33,300)*33^2 There is a similar equation for the change in the y coordinate: Voy*t + (1/2)(Fy/m)t^2

Thanks for the timely help.

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