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August 20, 2014

August 20, 2014

Posted by **lavonne** on Tuesday, November 23, 2010 at 4:52pm.

1. C(graphite) + O2(g) produces CO2(g), delta H = -393.5 kJ

2. H2(g) + 1/2 O2(g) produces H2O(l), delta H = -285.8 kJ

3. Ch3OH(l) + 3/2 O2(g) produces Co2(g) + 2H2O(l), delta H = -726.4 kJ

Given these calculate the enthalpy change for:

C(graphite) + 2H2(g) + 1/2 O2(g) produces CH3OH(l)Please help!

- chemistry -
**DrBob222**, Tuesday, November 23, 2010 at 5:52pmUse equation 1 as is. (delta H as is)

Add 2x equation 2 (and 2x delta H).

Reverse equation 3 and add to the other two (change the sign on delta H).

Then added the equations as noted and confirm you obtain the desired equation; finally, add the delta Hs (with changes as noted).

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