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April 18, 2014

Homework Help: chemistry

Posted by ben on Tuesday, November 23, 2010 at 4:43pm.

The pH of a solution prepared by mixing 45 mL of 0.183 M KOH and 65 mL of 0.145 M HCl is

i solved it but my answer is wrong. the right one is 1.97. am i missing a step?


moles of HCl left over = (moles of HCl) ( moles of KOH)
moles of HCl left over = (0.009425 mol) ( 0.008235 mol)
moles of HCl left over = 0.00119 mol or 1.19 10^-3 mol



[H+] = (moles H+) / (Liters of final solution)


[H+] = (1.19 10^-3 mol) / (0.110 L)
[H+] = 1.309 10^-4 M or 1.3 10^-4 M

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