Posted by **kaitlyn** on Tuesday, November 23, 2010 at 11:32am.

An 8.00 g bullet is fired into a 250 g block that is initially at rest at the edge of a table of 1.00 m height. The bullet remains in the block, and after the impact the block lands d = 1.8 m from the bottom of the table. Determine the initial speed of the bullet.

- momentum -
**MathMate**, Tuesday, November 23, 2010 at 11:38am
An almost identical problem has been answered twice. See:

http://www.jiskha.com/display.cgi?id=1290391597

- physics -
**drwls**, Tuesday, November 23, 2010 at 11:39am
Calculate how long it takes the block to reach the floor.

1.00 m = (g/2) t^2

t = 0.452 s

Then calculate the horizontal velocity component as it leaves the edge of the table

Vx = 1.8 m/0.452s = 3.98 m/s

Then use conservation of momentum to get the velocity of the bullet, v.

m v = (m+M) Vx

m is the bullet mass and M is the block's mass.

v = (258/8) Vx = ___

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