Posted by Emmanuel on Tuesday, November 23, 2010 at 5:08am.
I can't draw the circuit here, but i can analize the circuit:
a. Rt = 0.5 + 2 + (3 * 3) / (3 + 3) = 0.5 + 2 + 1.5 = 4 ohms = total
resistance in circuit.
b. The external circuit reduces the battery voltage.
c. I = V/Rt = 6 / 4 = 1.5Amps = the
current in circuit.
d. Vi = I*Ri = 1.5 * 0.5 = 0.75 volts
= Voltage drop across internal resistance.
e. The current divides equally between
the two 3 ohm resistors:
I3 = I / 2 = 1.5 / 2 = 0.75 Amps =
current thru each 3 ohm resistor.
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