Posted by **Emmanuel** on Tuesday, November 23, 2010 at 5:08am.

A battery of three cells in series each of emf 2v and internal 0.5 ohms is connected to 2ohms resistor in series with a parallel combination of two 3ohms resistors (a)draw the circult diagram (b)the effective of external resistance (c)the current in the circult (d)the lost volt in the battery (e)the current in one of the 3ohms resistor

- Physics -
**Henry**, Wednesday, November 24, 2010 at 6:29pm
I can't draw the circuit here, but i can analize the circuit:

a. Rt = 0.5 + 2 + (3 * 3) / (3 + 3) = 0.5 + 2 + 1.5 = 4 ohms = total

resistance in circuit.

b. The external circuit reduces the battery voltage.

c. I = V/Rt = 6 / 4 = 1.5Amps = the

current in circuit.

d. Vi = I*Ri = 1.5 * 0.5 = 0.75 volts

= Voltage drop across internal resistance.

e. The current divides equally between

the two 3 ohm resistors:

I3 = I / 2 = 1.5 / 2 = 0.75 Amps =

current thru each 3 ohm resistor.

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