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April 20, 2014

Homework Help: AP Calculus BC

Posted by APpreciative student on Tuesday, November 23, 2010 at 1:48am.

Hi! Thank you very much for your help---
I'm not sure what the answer to this is; how do I solve?

Find antiderivative of
(1/(x^2))[sec(1/x)][tan(1/x)]dx

I did integration by parts and got to
(1/(x^2))[sec(1/x)] + 2*[antiderivative of (1/(x^3))(sec(1/x))dx]

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