Posted by **Azur** on Tuesday, November 23, 2010 at 12:48am.

If the mass percentage of water in FeSO4 X H20 is 45.3%, find the number x?

- Chemistry -
**DrBob222**, Tuesday, November 23, 2010 at 12:57am
Take a 100 g sample.

45.3 g H2O

54.7 g FeSO4

Convert to moles.

54.7g/151.9 = 0.360

45.3/18 = 2.52

You want the FeSO4 to be 1 so we divide the FeSO4 by itself; i.e.,

0.360/0.360 = 1.00

Then to keep things equal we divide the moles H2O by the same value.

2.52/0.360 = 6.99 which rounds to 7 so the formula is

FeSO4.7H2O

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