Posted by **Avalon** on Monday, November 22, 2010 at 9:12pm.

A uniform piece of wire, 30 cm long, is bent in the center to give it an L-shape. How far from the bend is the center of mass?

I know that the center of mass is

([m1]x+[m2]x)/([m1]+m2]), but I don't quite understand how to apply it to this problem.

- Physics -
**MathMate**, Monday, November 22, 2010 at 11:35pm
Do the calculations separately in the x and the y directions.

Let each of the 15cm segments lie along the x, and y-axes, with the bend at the origin.

Apply

([m1]x+[m2]x)/([m1]+m2])

to get, along the x-axis:

m1=15, m2=15, x1=7.5, x2=0

x0=(m1x+m2x)/(m1+m2)

=(7.5*15+0)/(15+15)

=3.75

Solve similarly for y0.

## Answer this Question

## Related Questions

- Physics - I understand the basics of the center of mass, but I'm having a hard ...
- College physics - Center of mass - College Physics- Center of Mass? The objects ...
- physics - Consider a long wire where the current density is not uniform but ...
- Physics - A uniform rod of length 176 cm is bent at its midpoint into a right ...
- physics - A curcial part of a piece of machinery starts as a flat uniform ...
- physics - To balance a 29.8 kg automobile tire and wheel, a mechanic must place...
- physics - To balance a 40.8-kg automobile tire and wheel, a mechanic must place ...
- Physics - A weight of 50.0 N is hung from the center of a stretched horizontal ...
- Physics - A stiff uniform wire of mass M_0 and length L_0 is cut, bent, and the ...
- physics - A person of mass M lies on the floor doing leg raises. His leg is 0....

More Related Questions