Posted by **Milly** on Monday, November 22, 2010 at 8:08pm.

Problem:

Geoff has $5000 to invest. He wants to earn $568 in interest in one year. He will invest part of the money at 12% and the other part at 10%. How will he invest.

+I already know how to do Simplest Interest, I just can't read the problem to find what

i =

p =

r =

t =

- Algebra: Simple Interest -
**Brooke**, Monday, November 22, 2010 at 8:40pm
(5000 - x).12 + x(.10) = 568

(5000).12 - (x).12 + x(.10) = 568

600 - .12x + .1x = 568

subtract 600 from both sides

-.12x + .1x = -32

-.02x = -32

divide both sides by -.02

x = 1600

3400 at 12% and 1600 at 10%

- Algebra: Simple Interest -
**Mike**, Friday, December 3, 2010 at 8:33am
a loan of 25,000 its due in 9 months with an annual interest rate of 10%. Find the total amount that will be due.

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