By titration it is found that 68.9 mL of 0.122 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the concentration of the HCl solution.
mL acid x M acid = mL NaOH x M NaOH.
0.257
To calculate the concentration of the HCl solution, we can use the equation:
M1V1 = M2V2
where M1 is the concentration of the NaOH solution, V1 is the volume of NaOH solution used, M2 is the concentration of the HCl solution, and V2 is the volume of HCl solution used.
Given:
M1 = 0.122 M (concentration of NaOH solution)
V1 = 68.9 mL (volume of NaOH solution used)
V2 = 25.0 mL (volume of HCl solution used)
We want to find M2 (concentration of HCl solution).
Substituting the given values into the equation:
(0.122 M) * (68.9 mL) = M2 * (25.0 mL)
Now we can solve for M2:
M2 = (0.122 M * 68.9 mL) / (25.0 mL)
M2 = 0.3356 M
Therefore, the concentration of the HCl solution is 0.3356 M.