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January 25, 2015

January 25, 2015

Posted by **sandhu** on Monday, November 22, 2010 at 8:44am.

- physics -
**drwls**, Monday, November 22, 2010 at 12:51pmThe ball actually rises H = 19 feet, and falls an equal distance. The travel time of the baseball is twice the time it takes to rise or fall 19 feet. That total time is 2*sqrt[H/(2g)]= 1.086 seconds

The vertical velocity component when thrown is (0.543s)*g = 17.5 ft/s

The horizontal velocity component is (and remains) sqrt[124^2 - 17.5^2] = 122.8 ft/s

That should be multiplied by the flight time to get the distance of the throw.

- physics -
**sandhu**, Monday, November 22, 2010 at 8:59pmThanks

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