Posted by **sandhu** on Monday, November 22, 2010 at 8:44am.

An outfielder throws a baseball from the outfield to the third baseman. In flight, the ball reaches a height of 25 ft above the ground. The outfielder releases the ball from a height of 6 ft above the ground with a speed of 124 ft/sec. The ball is caught 6 ft above the ground by the third baseman. Determine the horizontal distance between the point where the ball is released and where it is caught

- physics -
**drwls**, Monday, November 22, 2010 at 12:51pm
The ball actually rises H = 19 feet, and falls an equal distance. The travel time of the baseball is twice the time it takes to rise or fall 19 feet. That total time is 2*sqrt[H/(2g)]= 1.086 seconds

The vertical velocity component when thrown is (0.543s)*g = 17.5 ft/s

The horizontal velocity component is (and remains) sqrt[124^2 - 17.5^2] = 122.8 ft/s

That should be multiplied by the flight time to get the distance of the throw.

- physics -
**sandhu**, Monday, November 22, 2010 at 8:59pm
Thanks

## Answer This Question

## Related Questions

- Math - A baseball player hits a baseball into the outfield. The equation h= -0....
- algebra - BASEBALL The equation h = –0.005x2 + x + 3 describes the path of a ...
- Alg1 - A baseball player hits a baseball into the outfield. The equation h= -0....
- Alg 1 quadratic functions - A baseball player hits a baseball into the outfield...
- Physics - An outfielder throws a 0.145 kg baseball to the shortstop with a ...
- physics - An outfielder throws a baseball with an initial speed of 30 m/s at an ...
- Physics - You toss a tennis ball straight upward. At the moment it leaves your ...
- physics - Julie throws a ball to her friend Sarah. The ball leaves Julie's hand ...
- Physics - You toss a tennis ball straight upward. At the moment it leaves your ...
- Physics - You toss a tennis ball straight upward. At the moment it leaves your ...

More Related Questions