Posted by **sandhu** on Monday, November 22, 2010 at 7:31am.

An 3730 kg airplane has a center of mass located 32 m from the front of the plane. A 123 kg man sits 25 m from the front of the plane. Where should a 76 kg woman sit so that the center of mass of the loaded plane is the same as the empty airplane? (m from front)

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**MathMate**, Monday, November 22, 2010 at 8:13am
Take moments about the centre of gravity (CG) the plane, so that the CG of the two persons is zero about the C from the front.

F........M...7...CG....X....W.......B

Take moments about the CG:

123 kg *7 m= 76 kg * X m

X = (123/76) * 7

= 11.33m (from the CG)

Distance from the front

=32+11.33 m

= 43.33 m from the front

- physics -
**sandhu**, Monday, November 22, 2010 at 8:41am
Thanks a lot

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