Posted by **Rob** on Sunday, November 21, 2010 at 11:33pm.

A gardener has 60 feet of fencing with which to enclose a garden adjacent to a long existing wall. The gardener will use the wall for one side and the available fencing for the remaining three sides.

(a) If the sides perpendicular to the wall have length x feet, which of the following represents the area A of the garden?

A(x) = –2x2 + 30x

A(x) = –2x2 + 60x

A(x) = x2 – 60x

A(x) = 2x2 – 60x

- Algebra -
**PsyDAG**, Monday, November 22, 2010 at 7:11am
Online "^" indicates an exponent.

Area = length * width

If x = length of each of the two sides, then the width = 60 - 2x

Thus the area = x(60-2x) = 60x - 2x^2

Unless you have a typo, I would not pick any of the choices.

## Answer this Question

## Related Questions

- Algebra Word Problem Help - A gardener has 40 feet of fencing with which to ...
- Algebra Word Problem Help - I got 2 more intense problems like this. Can someone...
- Algebra Help - I got 2 more intense problems like this. Can someone show me the ...
- Algebra Word Problem Help - A gardener has 40 feet of fencing with which to ...
- Algebra Word Problem Help - A gardener has 40 feet of fencing with which to ...
- Algebra - A builder has 80 feet of fencing to create an enclosure adjacent to a ...
- Algebra - Algebra Word Problems: 1. The length of the floor of a one-storey ...
- Math - A gardenervhas 100 meters of fencing to enclose two adjacent rectangular ...
- math - A gardener wants to use 62 feet of fencing to enclose a rectangular ...
- college algebra word problem - Here's the problem I was asked: You are visiting ...