# physics

posted by
**gabbi**
.

c) The rocket is launched a third time with the same initial velocity as before at an angle of 45 degrees. This time we want to launch the rocket so that it goes through a field goal post at a height of 7.9 meters in the air. Calculate the time the rocket will be in the air for. Calculate the horizontal distance in which the rocket must be placed from the field goal post.

(the initial velocity as before was 27.44.. when i multiply that by the sin and cos of 45 degrees i get 19.40301.. it's the same for each by the way.. so i use 19.40301 for the initial velocity for finding the time and horizontal distance.)