Posted by ... on Sunday, November 21, 2010 at 10:16pm.
0.50 m is presumably how far the spring is pulled back, not the displacement when the airplane leaves the catapult.
In this case, the energy acquired is (1/2) k X^2
k = 1.0*10^4 N/m
X = -.50 m
The answer will be in Joules
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