How do I write the equation of a line in STANDARD FORM, when it contains (-2,1) & (1,4) ?
First of all find the slope ...
slope = (4-1)/(1 + 2) = 3/3 = 1 , how nice!
using the point (1,4)
y - 4 = 1(x-1)
-x + y = 3
x - y = -3
Thank you so much!!!
I have been staring at this problem forever, haha :)
Thanks!
To write the equation of a line in standard form, you need to use the formula:
Ax + By = C
To find the values of A, B, and C, we need to follow these steps:
Step 1: Find the slope (m) of the line using the given points (-2,1) and (1,4).
- The formula to calculate the slope is: m = (y2 - y1) / (x2 - x1)
- Substituting the coordinates, the slope becomes: m = (4 - 1) / (1 - (-2)) = 3/3 = 1
Step 2: Use the slope-intercept form (y = mx + b) and substitute one of the given points to calculate the y-intercept (b).
- Using the point (-2,1), we have: 1 = 1*(-2) + b
- Solving for b, we get: 1 = -2 + b -> b = 3
Step 3: Substitute the slope (m) and the y-intercept (b) into the standard form equation.
- The equation is: y = mx + b -> y = x + 3
- Rearranging the equation to standard form: -x + y = 3
Therefore, the equation of the line in standard form when it contains the points (-2,1) and (1,4) is -x + y = 3.