What is the acceleration of a 23 kg pail of cement that is pulled upward (not sideways!) with a force of 300 N?
weight force down = 23*9.8 = 225 N
pull up = 300 N
Net force up = 300 - 225 = 75 N
a = F/m = 75/23
To find the acceleration of a 23 kg pail of cement being pulled upward with a force of 300 N, you need to make use of Newton's second law of motion. This law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
The formula for Newton's second law is:
F = m * a
Where:
F = net force acting on the object
m = mass of the object
a = acceleration of the object
Given the mass of the pail of cement (m = 23 kg) and the force applied (F = 300 N), we can rearrange the formula to solve for acceleration (a):
a = F / m
Plugging in the values, we get:
a = 300 N / 23 kg
Now, to calculate the acceleration, divide the force (300 N) by the mass (23 kg):
a ≈ 13.04 m/s^2
Therefore, the acceleration of the pail of cement being pulled upward with a force of 300 N is approximately 13.04 m/s^2.