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A microphone has an area of 3.8 cm2. It receives during a 2.87 s time period a sound energy of 4.2x10-11 J. What is the intensity of the sound?

  • Physics -

    (Sound Intensity) = (Energy)/[(Area)*(Time)]

    It can be converted to decibels using a logarithmic formula, if that is what they want.

  • Physics -

    How would I do that?

  • Physics -

    Do the indicated division first, to get 3.85*10^-8 W/m^2

    Zero dB corresponds to 10^-12 W/m^2

    Each factor of ten in intensity above the zero dB reference level corresponds to a 10 dB increase.

    I get 46 dB for your case

    for a better explanation

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