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March 30, 2017

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A 384-m wire is cut into three pieces. The second piece is 3 m longer than the first. The third is four-fifths as long as the first. How long is each piece?

  • Math - ,

    first ------> x
    second ----> x+3
    third -----> (4/5)x

    solve x + x+3 + (4/5)x = 384

    I suggest multiplying each term by 5, then it becomes real easy.

  • Math - ,

    F-lenght of first size
    S-lenght of second size
    T-lenght of third size

    S=F+3

    T=(4/5)*F

    F+S+T=F+F+3+(4/5)F=384

    2F+3+(4/5)F=384
    2F+(4/5)F=384-3
    2F+(4/5)F=381 Multiply with 5
    10F+4F=381*5
    14F=1905 Divide with 14

    F=1905/14

    S=F+3=(1905/14)+(42/14)
    Becouse (42/14)=3

    S=1947/14

    T=(4/5)*F=(4/5)*(1905/14)
    =(4/5)*[(3*5*127)/14]
    Becouse 1905=3*5*127

    T=(4*3*127)/(14)=1524/14

    T=1524/14

    F+S+T=(1905/14)+(1947/14)+(1524/14)
    =5376/14=384

  • Math - ,

    Pooo

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