Wednesday

April 16, 2014

April 16, 2014

Posted by **Max** on Sunday, November 21, 2010 at 2:13pm.

V(t)= 53+28.5sin(pie(t)/2-pie/2)

(a) Find the maximum and minimum amount of air in the lungs.

Maximum is (cubic inches)

Minimum is (cubic inches)

(b) How often does the person exhale?

every (seconds)

(c) How many breaths per minute does the person take?

- Precalculus -
**Reiny**, Sunday, November 21, 2010 at 2:29pmsin(pie(t)/2-pie/2) has a max of 1 and a min of -1

so V(t) has a max of 53 + 28.5(1) = 81.5

and a min of 53 + 28.5(-1) = 24.5

b) we need the period

period = 2π/(π/2) = 4

c) easy now

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