math
posted by mimz on .
solve the given inequality and graph its solution on the number line
2x/3less than or eqaul to (</) 32x/5
lxl less than or equal to 5
2 is less than or eqaul to lx6l less than or equal to 5

1.
2  x/3 < 3  2x/5
multiply by 15, the LCD
30  5x ≤ 45  6x
6x  5x ≤ 4530
x ≤ 15
2.
x ≤ 5
x ≤ 5 AND x≤5
x≤5 AND x≥5
in short notation: 5 ≤ x ≤ 5
3.
2 ≤ x6 ≤ 5
case1: 2 ≤ x6≤ 5
8 ≤ x ≤ 11
case2:
2 ≤ x+6≤ 5
4 ≤ x ≤ 1
4 ≥ x ≥ 1 or
1 ≤ x ≤ 4
so 8 ≤ x ≤ 11 OR 1 ≤ x ≤ 4