Posted by **mike** on Sunday, November 21, 2010 at 10:28am.

you have 95 coins that total $10.75. the coins consist of only quarters and nickels. how many of each coin do you have?

- algebra word problems -
**Jen**, Sunday, November 21, 2010 at 11:25am
.25q+.05n=10.75 (1)

q+n=95 (2)

Multiply (2) by -.25 to cancel the q's

.25q+.05n=10.75 (1)

-.25q-.25n=-23.75 (3)

-.2n=-13

Divide both sides by -.2

n=65

From (2), q+n=95, q+65=95, q=30

When plugged back into equation 1, it checks. It works in both equations, so this is your solution.

- algebra word problems -
**Tim**, Thursday, March 6, 2014 at 10:14pm
You have a total of $175 in $5 and $20 bills. The number of $5 bills you have is 3 more than 4 times the number of $20 bills. How many of each type of bill do you have?

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