What is the ionic equations for the following metals and aqueous substances? With the same equation what is being oxidize and what is being reduced?

Zn + AgNO3
Zn + CuSO4
Zn + PbNO3

Mg + AgNO3
Mg + CuSO4
Mg + PbNO3

Cu + AgNO3

Here is the first one. All of these are single replacement reactions.

Zn(s) + 2Ag^+(aq) ==> 2Ag(s) + Zn^+2(aq)

Oxidation is the loss of electrons; hence, Zn is oxidized. Ag ion is reduced.

To determine the ionic equations for these reactions and identify what is being oxidized and reduced, we need to first write the balanced chemical equations for these reactions:

1) Zn + AgNO3 --> Zn(NO3)2 + Ag
2) Zn + CuSO4 --> ZnSO4 + Cu
3) Zn + Pb(NO3)2 --> Zn(NO3)2 + Pb

4) Mg + AgNO3 --> Mg(NO3)2 + Ag
5) Mg + CuSO4 --> MgSO4 + Cu
6) Mg + Pb(NO3)2 --> Mg(NO3)2 + Pb

7) Cu + AgNO3 --> Cu(NO3)2 + Ag

Now, to determine what is being oxidized and reduced, we need to look at the changes in oxidation states of the elements involved.

In a redox reaction, oxidation is the process of losing electrons, while reduction is the process of gaining electrons.

In equations 1, 2, 4, 5, and 7, no changes occur in the oxidation states of the elements. Therefore, these reactions are not redox reactions.

In equations 3 and 6, the oxidation state of Zn and Mg change from 0 to +2. This indicates that Zn and Mg are being oxidized. On the other hand, the oxidation state of Pb increases from +2 to +4. Therefore, Pb is being reduced in equation 3. Similarly, the oxidation state of Pb increases from +2 to +4 in equation 6, indicating that Pb is also being reduced.

In equation 7, the oxidation state of Cu changes from 0 to +2, indicating that Cu is being oxidized.

To summarize:
- In equation 1: Zn is being oxidized and Ag is being reduced.
- In equation 2: Zn is being oxidized and Cu is being reduced.
- In equation 3: Zn is being oxidized and Pb is being reduced.
- In equation 4: Mg is being oxidized and Ag is being reduced.
- In equation 5: Mg is being oxidized and Cu is being reduced.
- In equation 6: Mg is being oxidized and Pb is being reduced.
- In equation 7: Cu is being oxidized and Ag is being reduced.