Saturday

December 20, 2014

December 20, 2014

Posted by **Karen** on Saturday, November 20, 2010 at 3:14pm.

Solve the system by substitution or elimination.

2x+y=1

3x-y=14

Answer: (3,5)

x-3y= -12

2x + 11y= -7

Answer: (39,17)

4x+2y=8

12x+6y=24

Answer: no solution

4x-2y=5

2x-y= -1

Answer: no solution

4a+3b =6

8a-b= -9

Answer: no solution

- Algebra 2/Math -
**Damon**, Saturday, November 20, 2010 at 3:17pm2x+y=1

3x-y=14

Answer: (3,5)

------------------------

Hey, you can check easily. Just put the values in for x and y

2(3)+5 = 8 not 1 - NO WAY

- Algebra 2/Math -
**bobpursley**, Saturday, November 20, 2010 at 3:17pmon the last

4a+3b=6

24a-3b=-27 ( I multiplied by 3), then add

28a=-19

why did you get no solution?

others are correct.

- Algebra 2/Math -
**Reiny**, Saturday, November 20, 2010 at 3:30pmFirst one should be (3,-5)

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