Posted by Karen on Saturday, November 20, 2010 at 3:14pm.
Can you check these thanks.
Solve the system by substitution or elimination.
2x+y=1
3xy=14
Answer: (3,5)
x3y= 12
2x + 11y= 7
Answer: (39,17)
4x+2y=8
12x+6y=24
Answer: no solution
4x2y=5
2xy= 1
Answer: no solution
4a+3b =6
8ab= 9
Answer: no solution

Algebra 2/Math  Damon, Saturday, November 20, 2010 at 3:17pm
2x+y=1
3xy=14
Answer: (3,5)

Hey, you can check easily. Just put the values in for x and y
2(3)+5 = 8 not 1  NO WAY

Algebra 2/Math  bobpursley, Saturday, November 20, 2010 at 3:17pm
on the last
4a+3b=6
24a3b=27 ( I multiplied by 3), then add
28a=19
why did you get no solution?
others are correct.

Algebra 2/Math  Reiny, Saturday, November 20, 2010 at 3:30pm
First one should be (3,5)
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