posted by melissa on .
what is the molarity of ZnCl2 that forms when 30.0 g of zinc completely reacts with CuCl2 according to the following reaction? Assume a final volume of 285 mL.
Zn(s) + CuCl2(aq)--> ZnCl2(aq) + Cu(s)
Use the following example of a stoichiometry problem to convert 30.0 g Zn to moles ZnCl2.Just follow the steps.
Then M = moles/L (0.285 L from the problem).