posted by Pronab on .
Q 2) A particle executes simple harmonic motion with an amplitude of 10 cm. At what distance from the mean position are the kinetic and potential energies equal ?
Consider a simple haemonic motion of time period T . Calculate the time taken for the displacement to change value from half the amplitude to the amplitude.
KE is half of the total energy when the potential energy is also half the total. Since PE is proportional to displacement^2, the displacement would be sqrt(1/2) = 70.7% of the maximum value.
Please post followup questions separately