Posted by **Lynne** on Saturday, November 20, 2010 at 12:17am.

I am really confused...can someone help me with this? I am supposed to graph solution of given system of linear inequality:

y is greater than 4x-3

y is less than or equal to x+2

- graphing linear equatios -
**SraJMcGin**, Saturday, November 20, 2010 at 2:14am
Hopefully some of these tutorials will help you:

http://search.yahoo.com/search?fr=mcafee&p=graphing+linear+inequality+tutorials

Sra

- graphing linear equatios -
**Reiny**, Saturday, November 20, 2010 at 9:32am
Consider the "equation" of the corresponding function, I will use yours as an example

y = 4x-3

Since it is a straight line, all you need are two points

since you had

y > 4x - 3, draw a dotted line to show that the points are excluded.

Shade in the region **above** that line

If the relation had been

y < 4x-3 , you would shade in the region **below** the line

If the relation had been ≥ or ≤ , you would make the boundary line solid, to show the points on the line would be included.

my explanation applies to all inequations of the form

y > f(x), y < f(x), y ≥ f(x), or y ≤ f(x)

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