Posted by Lynne on Saturday, November 20, 2010 at 12:17am.
I am really confused...can someone help me with this? I am supposed to graph solution of given system of linear inequality:
y is greater than 4x-3
y is less than or equal to x+2
graphing linear equatios - SraJMcGin, Saturday, November 20, 2010 at 2:14am
Hopefully some of these tutorials will help you:
graphing linear equatios - Reiny, Saturday, November 20, 2010 at 9:32am
Consider the "equation" of the corresponding function, I will use yours as an example
y = 4x-3
Since it is a straight line, all you need are two points
since you had
y > 4x - 3, draw a dotted line to show that the points are excluded.
Shade in the region above that line
If the relation had been
y < 4x-3 , you would shade in the region below the line
If the relation had been ≥ or ≤ , you would make the boundary line solid, to show the points on the line would be included.
my explanation applies to all inequations of the form
y > f(x), y < f(x), y ≥ f(x), or y ≤ f(x)
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