Posted by **Ed** on Friday, November 19, 2010 at 11:32pm.

What minimum coefficient of friction between the tires and the road will allow a 3700 kg truck to navigate an unbanked curve of radius 25 m at a speed of 45 km/h?

My answer:

Fnet=ma

Ff=m(v2)/r)

Ff=(3700)(452/25)

Ff=(3700)(2025/25)

Ff=(3700)(81)

Ff=299700

Frictional force

Ff=Fnµ

299700=(3700)(9.8)µ

299700=36260µ

µ= 8.3

Is this right? Thanks for your help.

## Answer This Question

## Related Questions

- physics - A 1 500-kg car rounds an unbanked curve with a radius of 52 m at a ...
- physics 1401!!! - A 2000-kg car rounds an unbanked curve with a radius of 45 m ...
- physics - An unbanked curve has a radius of curvature of 75m. On a winter day, ...
- physics - An unbanked curve has a radius of curvature of 75m. On a winter day, ...
- physics - An unbanked curve has a radius of curvature of 75m. On a winter day, ...
- Physics - A 14,300 N car traveling at 46.0 km/h rounds a curve of radius 2.30 x ...
- physics - meerany A flat (unbanked) curve on a highway has a radius of 220.0 Ill...
- physics - a 2400-lb (=10.7-kn)car traveling at 30 mi/h (=13.4m/s)attempts to ...
- physics - Radius of Curvature A bicyclist traveling at 8 m/s rides around an ...
- physics - A crate of eggs is located in the middle of the flat bed of a pickup ...

More Related Questions