Posted by Jen on Friday, November 19, 2010 at 7:51pm.
ACD has half the area if the rectangle.
AEB is less than half of the rectangle, and its fraction of the whole depends upon the aspect ratio (AB/BC) of the triangle.
More information is needed to answer the question.
In a rectangle, the diagonals bisect each other giving you four triangles of equal area.
so triangle ACD = 16
Whoops! I forgot that equal-area theorem. Thanks again, Reiny.
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