Posted by **Jen** on Friday, November 19, 2010 at 7:51pm.

Rectangle ABCD has diagonals AC and BD. E is the point of intersection of the two diagonals. If the area of triangle AEB is 8, what is the area of triangle ACD?

- Geometry -
**drwls**, Friday, November 19, 2010 at 8:12pm
ACD has half the area if the rectangle.

AEB is less than half of the rectangle, and its fraction of the whole depends upon the aspect ratio (AB/BC) of the triangle.

More information is needed to answer the question.

- Geometry -
**Reiny**, Friday, November 19, 2010 at 9:04pm
In a rectangle, the diagonals bisect each other giving you four triangles of equal area.

so triangle ACD = 16

- Geometry -
**drwls**, Saturday, November 20, 2010 at 8:34am
Whoops! I forgot that equal-area theorem. Thanks again, Reiny.

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